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app.pariksha.tech/evaluate/25421970
ParikshAI Enterprise
Evaluation Mode
Rishabh Galkar
Evaluator
RG
Scoring40.0/70(57.1%)
1
Q1
9/14
2
Q2
4.5/14
3
Q3
10.5/14
Part A
2.5
/3
or
Part A (OR)
/3
Part C
5
/7
or
Part C (OR)
/7
Part B
3
/4
or
Part B (OR)
/4
Optional note...
4
Q4
6.5/14
5
Q5
9.5/14
Submit Evaluation
25421970 · Network Theory|12 / 33⊕ 120%
DO NOT WRITE ANYTHING IN THIS PORTION

Q : 3

a) Initial Value Theorem.

By Initial Value Theorem :

lim f(t)  =  lim s · F(s)
t→0⁺s→∞

Given: F(s) = (2s + 1) / s(s + 2)

∴ lim s · F(s)

s→∞

= lim s(2s+1) / s(s+2)

= lim (2s+1) / (s+2)

=  2

T
AI Score83%
2.5/ 383%
+2.5m earned
AI Reasoning

Student correctly states the Initial Value Theorem and applies it to F(s) = (2s+1)/s(s+2). Limit computation and final value of 2 are accurate. Minor deduction for missing intermediate step notation.

Found on page: 12

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Step 01 · Rubrics Studio

Define Grading Criteria

QuestionQ2(a) — Time Constant ▾
12 marks
CriterionMarks
Concept Definition
3m
Formula & Derivation
4m
Worked Example
3m
Units & Notation
2m
Step 02 · AI Engine

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Batch #4521 · Live70%
012,000 scripts
Evaluated8,421
High Conf. (>80%)7,980
Flagged (<50% conf.)441
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Step 03 · Evaluator Portal

Human Verify & Lock

Script #45102 · Low confidence flag
43% conf.

Q2(a) — What is Time Constant.

time constant equation follow.

= I · e-t/T / T0

AI Score43% conf. — needs review
5/ 10
Concept Definition3/3
Formula & Derivation2/4
Worked Example0/3
Human review required
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8,421
AI Graded
441
Flagged
94.8%
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